Pamela made a profit of 60% from the sale of a blazer and a profit of 70% from the sale of a dress. The total profit she made from the two items was $159. She later sold a similar blazer at a discount of 20% off the advertised price. Her total profit for the three items then increased to $184.20.

1. Find the profit made on the dress.
2. How much did she sell the dress for?

	Blazer 1	Dress 1	Blazer 2
Cost Price	5 u	10 p	5 u
Profit	+ 3 u	+ 7 p	+ 3 u
Selling Price	8 u	17 p	8 u
Discount			- 1.6 u
Discounted Price			6.4 u

100% + 60% = 160%
160% = ¹⁶⁰₁₀₀ = ⁸₅

100% + 70% = 170%
170% = ¹⁷⁰₁₀₀ = ¹⁷₁₀

(a)
Selling price of the blazer
= 100% of the price of the blazer + 60% of the price of the blazer
= 5 u + 3 u
= 8 u

Selling price of the dress
= 100% of the price of the dress + 70% of the price of the dress
= 10 p + 7 p
= 17 p

Price of the second blazer after 20% discount in percentage
= 100% - 20%
= 80%

Price of the second blazer after 20% discount in units
= 80% x 8 u
= ⁸⁰₁₀₀ x 8 u
= 6.4 u

Profit made for the second blazer in units
= 6.4 u - 5 u
= 1.4 u

1.4 u = 184.2 - 159 = 25.2

1 u = 25.2 ÷ 1.4 = 18

3 u + 7 p = 159
3 x 18 + 7 p = 159
54 + 7 p = 159

7 p
= 159 - 54
= $105

Profit made on the dress = $105

(b)
1 p = 105 ÷ 7 = 15

Selling price of the dress
= 17 p
= 17 x 15
= $255

Answer(s): (a) $105; (b) $255