Hazel made a profit of 60% from the sale of a jacket and a profit of 70% from the sale of a coat. The total profit she made from the two items was $162. She later sold a similar jacket at a discount of 20% off the advertised price. Her total profit for the three items then increased to $188.60.
- Find the profit made on the coat.
- How much did she sell the coat for?
|
Jacket 1 |
Coat 1 |
Jacket 2 |
Cost Price |
5 u |
10 p |
5 u |
Profit |
+ 3 u |
+ 7 p |
+ 3 u |
Selling Price |
8 u |
17 p |
8 u |
Discount |
|
|
- 1.6 u |
Discounted Price |
|
|
6.4 u |
100% + 60% = 160%
160% =
160100 =
85100% + 70% = 170%
170% =
170100 =
1710(a)
Selling price of the jacket
= 100% of the price of the jacket + 60% of the price of the jacket
= 5 u + 3 u
= 8 u
Selling price of the coat
= 100% of the price of the coat + 70% of the price of the coat
= 10 p + 7 p
= 17 p
Price of the second jacket after 20% discount in percentage
= 100% - 20%
= 80%
Price of the second jacket after 20% discount in units
= 80% x 8 u
=
80100 x 8 u
= 6.4 u
Profit made for the second jacket in units
= 6.4 u - 5 u
= 1.4 u
1.4 u = 188.6 - 162 = 26.6
1 u = 26.6 ÷ 1.4 = 19
3 u + 7 p = 162
3 x 19 + 7 p = 162
57 + 7 p = 162
7 p
= 162 - 57
= $105
Profit made on the coat = $105
(b)
1 p = 105 ÷ 7 = 15
Selling price of the coat
= 17 p
= 17 x 15
= $255
Answer(s): (a) $105; (b) $255