Opal made a profit of 50% from the sale of a dress and a profit of 60% from the sale of a blouse. The total profit she made from the two items was $53. She later sold a similar dress at a discount of 10% off the advertised price. Her total profit for the three items then increased to $62.80.

1. Find the profit made on the blouse.
2. How much did she sell the blouse for?

	Dress 1	Blouse 1	Dress 2
Cost Price	2 u	5 p	2 u
Profit	+ 1 u	+ 3 p	+ 1 u
Selling Price	3 u	8 p	3 u
Discount			- 0.3 u
Discounted Price			2.7 u

100% + 50% = 150%
150% = ¹⁵⁰₁₀₀ = ³₂

100% + 60% = 160%
160% = ¹⁶⁰₁₀₀ = ⁸₅

(a)
Selling price of the dress
= 100% of the price of the dress + 50% of the price of the dress
= 2 u + 1 u
= 3 u

Selling price of the blouse
= 100% of the price of the blouse + 60% of the price of the blouse
= 5 p + 3 p
= 8 p

Price of the second dress after 10% discount in percentage
= 100% - 10%
= 90%

Price of the second dress after 10% discount in units
= 90% x 3 u
= ⁹⁰₁₀₀ x 3 u
= 2.7 u

Profit made for the second dress in units
= 2.7 u - 2 u
= 0.7 u

0.7 u = 62.8 - 53 = 9.8

1 u = 9.8 ÷ 0.7 = 14

1 u + 3 p = 53
1 x 14 + 3 p = 53
14 + 3 p = 53

3 p
= 53 - 14
= $39

Profit made on the blouse = $39

(b)
1 p = 39 ÷ 3 = 13

Selling price of the blouse
= 8 p
= 8 x 13
= $104

Answer(s): (a) $39; (b) $104