Hazel made a profit of 50% from the sale of a shirt and a profit of 70% from the sale of a windbreaker. The total profit she made from the two items was $60. She later sold a similar shirt at a discount of 25% off the advertised price. Her total profit for the three items then increased to $62.75.

1. Find the profit made on the windbreaker.
2. How much did she sell the windbreaker for?

	Shirt 1	Windbreaker 1	Shirt 2
Cost Price	2 u	10 p	2 u
Profit	+ 1 u	+ 7 p	+ 1 u
Selling Price	3 u	17 p	3 u
Discount			- 0.75 u
Discounted Price			2.25 u

100% + 50% = 150%
150% = ¹⁵⁰₁₀₀ = ³₂

100% + 70% = 170%
170% = ¹⁷⁰₁₀₀ = ¹⁷₁₀

(a)
Selling price of the shirt
= 100% of the price of the shirt + 50% of the price of the shirt
= 2 u + 1 u
= 3 u

Selling price of the windbreaker
= 100% of the price of the windbreaker + 70% of the price of the windbreaker
= 10 p + 7 p
= 17 p

Price of the second shirt after 25% discount in percentage
= 100% - 25%
= 75%

Price of the second shirt after 25% discount in units
= 75% x 3 u
= ⁷⁵₁₀₀ x 3 u
= 2.25 u

Profit made for the second shirt in units
= 2.25 u - 2 u
= 0.25 u

0.25 u = 62.75 - 60 = 2.75

1 u = 2.75 ÷ 0.25 = 11

1 u + 7 p = 60
1 x 11 + 7 p = 60
11 + 7 p = 60

7 p
= 60 - 11
= $49

Profit made on the windbreaker = $49

(b)
1 p = 49 ÷ 7 = 7

Selling price of the windbreaker
= 17 p
= 17 x 7
= $119

Answer(s): (a) $49; (b) $119