Xylia made a profit of 60% from the sale of a dress and a profit of 80% from the sale of a jacket. The total profit she made from the two items was $79. She later sold a similar dress at a discount of 30% off the advertised price. Her total profit for the three items then increased to $84.40.
- Find the profit made on the jacket.
- How much did she sell the jacket for?
|
Dress 1 |
Jacket 1 |
Dress 2 |
Cost Price |
5 u |
5 p |
5 u |
Profit |
+ 3 u |
+ 4 p |
+ 3 u |
Selling Price |
8 u |
9 p |
8 u |
Discount |
|
|
- 2.4 u |
Discounted Price |
|
|
5.6 u |
100% + 60% = 160%
160% =
160100 =
85100% + 80% = 180%
180% =
180100 =
95(a)
Selling price of the dress
= 100% of the price of the dress + 60% of the price of the dress
= 5 u + 3 u
= 8 u
Selling price of the jacket
= 100% of the price of the jacket + 80% of the price of the jacket
= 5 p + 4 p
= 9 p
Price of the second dress after 30% discount in percentage
= 100% - 30%
= 70%
Price of the second dress after 30% discount in units
= 70% x 8 u
=
70100 x 8 u
= 5.6 u
Profit made for the second dress in units
= 5.6 u - 5 u
= 0.6 u
0.6 u = 84.4 - 79 = 5.4
1 u = 5.4 ÷ 0.6 = 9
3 u + 4 p = 79
3 x 9 + 4 p = 79
27 + 4 p = 79
4 p
= 79 - 27
= $52
Profit made on the jacket = $52
(b)
1 p = 52 ÷ 4 = 13
Selling price of the jacket
= 9 p
= 9 x 13
= $117
Answer(s): (a) $52; (b) $117