Sabrina made a profit of 50% from the sale of a windbreaker and a profit of 70% from the sale of a jacket. The total profit she made from the two items was $65. She later sold a similar windbreaker at a discount of 25% off the advertised price. Her total profit for the three items then increased to $67.25.
- Find the profit made on the jacket.
- How much did she sell the jacket for?
|
Windbreaker 1 |
Jacket 1 |
Windbreaker 2 |
Cost Price |
2 u |
10 p |
2 u |
Profit |
+ 1 u |
+ 7 p |
+ 1 u |
Selling Price |
3 u |
17 p |
3 u |
Discount |
|
|
- 0.75 u |
Discounted Price |
|
|
2.25 u |
100% + 50% = 150%
150% =
150100 =
32100% + 70% = 170%
170% =
170100 =
1710(a)
Selling price of the windbreaker
= 100% of the price of the windbreaker + 50% of the price of the windbreaker
= 2 u + 1 u
= 3 u
Selling price of the jacket
= 100% of the price of the jacket + 70% of the price of the jacket
= 10 p + 7 p
= 17 p
Price of the second windbreaker after 25% discount in percentage
= 100% - 25%
= 75%
Price of the second windbreaker after 25% discount in units
= 75% x 3 u
=
75100 x 3 u
= 2.25 u
Profit made for the second windbreaker in units
= 2.25 u - 2 u
= 0.25 u
0.25 u = 67.25 - 65 = 2.25
1 u = 2.25 ÷ 0.25 = 9
1 u + 7 p = 65
1 x 9 + 7 p = 65
9 + 7 p = 65
7 p
= 65 - 9
= $56
Profit made on the jacket = $56
(b)
1 p = 56 ÷ 7 = 8
Selling price of the jacket
= 17 p
= 17 x 8
= $136
Answer(s): (a) $56; (b) $136