Gem made a profit of 50% from the sale of a windbreaker and a profit of 80% from the sale of a jacket. The total profit she made from the two items was $93. She later sold a similar windbreaker at a discount of 25% off the advertised price. Her total profit for the three items then increased to $96.25.

1. Find the profit made on the jacket.
2. How much did she sell the jacket for?

	Windbreaker 1	Jacket 1	Windbreaker 2
Cost Price	2 u	5 p	2 u
Profit	+ 1 u	+ 4 p	+ 1 u
Selling Price	3 u	9 p	3 u
Discount			- 0.75 u
Discounted Price			2.25 u

100% + 50% = 150%
150% = ¹⁵⁰₁₀₀ = ³₂

100% + 80% = 180%
180% = ¹⁸⁰₁₀₀ = ⁹₅

(a)
Selling price of the windbreaker
= 100% of the price of the windbreaker + 50% of the price of the windbreaker
= 2 u + 1 u
= 3 u

Selling price of the jacket
= 100% of the price of the jacket + 80% of the price of the jacket
= 5 p + 4 p
= 9 p

Price of the second windbreaker after 25% discount in percentage
= 100% - 25%
= 75%

Price of the second windbreaker after 25% discount in units
= 75% x 3 u
= ⁷⁵₁₀₀ x 3 u
= 2.25 u

Profit made for the second windbreaker in units
= 2.25 u - 2 u
= 0.25 u

0.25 u = 96.25 - 93 = 3.25

1 u = 3.25 ÷ 0.25 = 13

1 u + 4 p = 93
1 x 13 + 4 p = 93
13 + 4 p = 93

4 p
= 93 - 13
= $80

Profit made on the jacket = $80

(b)
1 p = 80 ÷ 4 = 20

Selling price of the jacket
= 9 p
= 9 x 20
= $180

Answer(s): (a) $80; (b) $180