Tina made a profit of 60% from the sale of a sweater and a profit of 70% from the sale of a jacket. The total profit she made from the two items was $127. She later sold a similar sweater at a discount of 20% off the advertised price. Her total profit for the three items then increased to $143.80.
- Find the profit made on the jacket.
- How much did she sell the jacket for?
|
Sweater 1 |
Jacket 1 |
Sweater 2 |
Cost Price |
5 u |
10 p |
5 u |
Profit |
+ 3 u |
+ 7 p |
+ 3 u |
Selling Price |
8 u |
17 p |
8 u |
Discount |
|
|
- 1.6 u |
Discounted Price |
|
|
6.4 u |
100% + 60% = 160%
160% =
160100 =
85100% + 70% = 170%
170% =
170100 =
1710(a)
Selling price of the sweater
= 100% of the price of the sweater + 60% of the price of the sweater
= 5 u + 3 u
= 8 u
Selling price of the jacket
= 100% of the price of the jacket + 70% of the price of the jacket
= 10 p + 7 p
= 17 p
Price of the second sweater after 20% discount in percentage
= 100% - 20%
= 80%
Price of the second sweater after 20% discount in units
= 80% x 8 u
=
80100 x 8 u
= 6.4 u
Profit made for the second sweater in units
= 6.4 u - 5 u
= 1.4 u
1.4 u = 143.8 - 127 = 16.8
1 u = 16.8 ÷ 1.4 = 12
3 u + 7 p = 127
3 x 12 + 7 p = 127
36 + 7 p = 127
7 p
= 127 - 36
= $91
Profit made on the jacket = $91
(b)
1 p = 91 ÷ 7 = 13
Selling price of the jacket
= 17 p
= 17 x 13
= $221
Answer(s): (a) $91; (b) $221