Jaslyn baked 140 wafers. 25% of them were vanila wafers. How many more vanila wafers must Jaslyn bake so that 85% of her wafers are vanila wafers?
| |
Vanila wafers |
Other wafers |
| Before |
25% |
75% |
| Change |
+ ? |
No change |
| After |
85 u |
15 u |
Number of vanila wafers at first
= 25% x 140
=
25100 x 140
= 35
Percentage of other wafers
= 100% - 25%
= 75%
Number of other wafers
= 75% x 140
=
75100 x 140
= 105
Number of other wafers in the end
= 100 u - 85 u
= 15 u
The number of other wafers remains unchanged.
75% = 15 u
15 u = 105
1 u = 105 ÷ 15 = 7
Number of vanila wafers in the end
= 85 u
= 85 x 7
= 595
Additional number of vanila wafers that Jaslyn must bake
= 595 - 35
= 560
Answer(s): 560
