Paul had a piece of wire 160 cm long. He used it to form a rectangle with its length and breadth in the ratio 3 : 2.
- What is the length of the rectangle?
- What is the area of the rectangle?
(a)
Length of the rectangle = 3 u
Breadth of the rectangle = 2 u
Perimeter of the rectangle
= 2 x 3 u + 2 x 2 u
= 6 u + 4 u
= 10 u
10 u = 160
1 u = 160 ÷ 10 = 16
Length of the rectangle
= 3 u
= 3 x 16
= 48 cm
(b)
Breadth of the rectangle
= 2 u
= 2 x 16
= 32 cm
Area of the rectangle
= 48 x 32
= 1536 cm
2 Answer(s): (a) 48 cm; (b) 1536 cm
2