The ratio of the number of pomegranates to the number of oranges that a fruit seller had was 3 : 10. After he sold one fifth of the oranges, there were a total of 385 pomegranates and oranges left at the shop.
- How many pomegranates were there at the shop?
- If he sold the remaining oranges in bags of 4 at $8.30 per bag, how much would he receive for them?
(a)
|
Pomegranates |
Oranges |
Total |
Before |
3x5 = 15 u
|
10x5 = 50 u |
|
Change |
|
- 10 u |
|
After |
15 u |
40 u |
385 |
The total number of oranges at first is the repeated identity.
LCM of 10 and 5 = 50
15 u + 40 u = 55 u
55 u = 385
1 u = 385 ÷ 55 = 7
Number of pomegranates in the stall
= 15 u
= 15 x 7
= 105
(b)
Number of oranges left
= 40 u
= 40 x 7
= 280
Number of bags
= 280 ÷ 4
= 70
Amount that he would receive
= 70 x 8.30
= $581
Answer(s): (a) 105; (b) $581