The ratio of the number of papayas to the number of lemons that a fruit seller had was 3 : 10. After he sold one quarter of the lemons, there were a total of 336 papayas and lemons left at the supermarket.
- How many papayas were there at the supermarket?
- If he sold the remaining lemons in bags of 4 at $2.90 per bag, how much would he receive for them?
(a)
|
Papayas |
Lemons |
Total |
Before |
3x4 = 12 u
|
10x4 = 40 u |
|
Change |
|
- 10 u |
|
After |
12 u |
30 u |
336 |
The total number of lemons at first is the repeated identity.
LCM of 10 and 4 = 40
12 u + 30 u = 42 u
42 u = 336
1 u = 336 ÷ 42 = 8
Number of papayas in the stall
= 12 u
= 12 x 8
= 96
(b)
Number of lemons left
= 30 u
= 30 x 8
= 240
Number of bags
= 240 ÷ 4
= 60
Amount that he would receive
= 60 x 2.90
= $174
Answer(s): (a) 96; (b) $174