The ratio of the number of kiwis to the number of apricots that a fruit seller had was 2 : 9. After he sold one third of the apricots, there were a total of 336 kiwis and apricots left at the market.
- How many kiwis were there at the market?
- If he sold the remaining apricots in bags of 7 at $8.50 per bag, how much would he receive for them?
(a)
|
Kiwis |
Apricots |
Total |
Before |
2x3 = 6 u
|
9x3 = 27 u |
|
Change |
|
- 9 u |
|
After |
6 u |
18 u |
336 |
The total number of apricots at first is the repeated identity.
LCM of 9 and 3 = 27
6 u + 18 u = 24 u
24 u = 336
1 u = 336 ÷ 24 = 14
Number of kiwis in the stall
= 6 u
= 6 x 14
= 84
(b)
Number of apricots left
= 18 u
= 18 x 14
= 252
Number of bags
= 252 ÷ 7
= 36
Amount that he would receive
= 36 x 8.50
= $306
Answer(s): (a) 84; (b) $306