The ratio of the number of peaches to the number of papayas that a fruit seller had was 3 : 8. After he sold one fifth of the papayas, there were a total of 705 peaches and papayas left at the supermarket.
- How many peaches were there at the supermarket?
- If he sold the remaining papayas in bags of 4 at $8.50 per bag, how much would he receive for them?
(a)
|
Peaches |
Papayas |
Total |
Before |
3x5 = 15 u
|
8x5 = 40 u |
|
Change |
|
- 8 u |
|
After |
15 u |
32 u |
705 |
The total number of papayas at first is the repeated identity.
LCM of 8 and 5 = 40
15 u + 32 u = 47 u
47 u = 705
1 u = 705 ÷ 47 = 15
Number of peaches in the stall
= 15 u
= 15 x 15
= 225
(b)
Number of papayas left
= 32 u
= 32 x 15
= 480
Number of bags
= 480 ÷ 4
= 120
Amount that he would receive
= 120 x 8.50
= $1020
Answer(s): (a) 225; (b) $1020