The ratio of the number of apricots to the number of limes that a fruit seller had was 3 : 10. After he sold one fifth of the limes, there were a total of 495 apricots and limes left at the mart.
- How many apricots were there at the mart?
- If he sold the remaining limes in bags of 6 at $6.90 per bag, how much would he receive for them?
(a)
|
Apricots |
Limes |
Total |
Before |
3x5 = 15 u
|
10x5 = 50 u |
|
Change |
|
- 10 u |
|
After |
15 u |
40 u |
495 |
The total number of limes at first is the repeated identity.
LCM of 10 and 5 = 50
15 u + 40 u = 55 u
55 u = 495
1 u = 495 ÷ 55 = 9
Number of apricots in the stall
= 15 u
= 15 x 9
= 135
(b)
Number of limes left
= 40 u
= 40 x 9
= 360
Number of bags
= 360 ÷ 6
= 60
Amount that he would receive
= 60 x 6.90
= $414
Answer(s): (a) 135; (b) $414