The ratio of the number of peaches to the number of grapefruits that a fruit seller had was 3 : 10. After he sold one half of the grapefruits, there were a total of 224 peaches and grapefruits left at the shop.
- How many peaches were there at the shop?
- If he sold the remaining grapefruits in bags of 7 at $6.30 per bag, how much would he receive for them?
(a)
|
Peaches |
Grapefruits |
Total |
Before |
3x2 = 6 u
|
10x2 = 20 u |
|
Change |
|
- 10 u |
|
After |
6 u |
10 u |
224 |
The total number of grapefruits at first is the repeated identity.
LCM of 10 and 2 = 20
6 u + 10 u = 16 u
16 u = 224
1 u = 224 ÷ 16 = 14
Number of peaches in the stall
= 6 u
= 6 x 14
= 84
(b)
Number of grapefruits left
= 10 u
= 10 x 14
= 140
Number of bags
= 140 ÷ 7
= 20
Amount that he would receive
= 20 x 6.30
= $126
Answer(s): (a) 84; (b) $126