The ratio of the number of papayas to the number of peaches that a fruit seller had was 2 : 5. After he sold one third of the peaches, there were a total of 96 papayas and peaches left at the shop.
- How many papayas were there at the shop?
- If he sold the remaining peaches in bags of 5 at $7.50 per bag, how much would he receive for them?
(a)
|
Papayas |
Peaches |
Total |
Before |
2x3 = 6 u
|
5x3 = 15 u |
|
Change |
|
- 5 u |
|
After |
6 u |
10 u |
96 |
The total number of peaches at first is the repeated identity.
LCM of 5 and 3 = 15
6 u + 10 u = 16 u
16 u = 96
1 u = 96 ÷ 16 = 6
Number of papayas in the stall
= 6 u
= 6 x 6
= 36
(b)
Number of peaches left
= 10 u
= 10 x 6
= 60
Number of bags
= 60 ÷ 5
= 12
Amount that he would receive
= 12 x 7.50
= $90
Answer(s): (a) 36; (b) $90