The ratio of the number of papayas to the number of plums that a fruit seller had was 3 : 10. After he sold one half of the plums, there were a total of 224 papayas and plums left at the market.
- How many papayas were there at the market?
- If he sold the remaining plums in bags of 7 at $2.90 per bag, how much would he receive for them?
(a)
|
Papayas |
Plums |
Total |
Before |
3x2 = 6 u
|
10x2 = 20 u |
|
Change |
|
- 10 u |
|
After |
6 u |
10 u |
224 |
The total number of plums at first is the repeated identity.
LCM of 10 and 2 = 20
6 u + 10 u = 16 u
16 u = 224
1 u = 224 ÷ 16 = 14
Number of papayas in the stall
= 6 u
= 6 x 14
= 84
(b)
Number of plums left
= 10 u
= 10 x 14
= 140
Number of bags
= 140 ÷ 7
= 20
Amount that he would receive
= 20 x 2.90
= $58
Answer(s): (a) 84; (b) $58