The ratio of the number of pears to the number of oranges that a fruit seller had was 3 : 10. After he sold one third of the oranges, there were a total of 290 pears and oranges left at the stall.
- How many pears were there at the stall?
- If he sold the remaining oranges in bags of 4 at $8.50 per bag, how much would he receive for them?
(a)
|
Pears |
Oranges |
Total |
Before |
3x3 = 9 u
|
10x3 = 30 u |
|
Change |
|
- 10 u |
|
After |
9 u |
20 u |
290 |
The total number of oranges at first is the repeated identity.
LCM of 10 and 3 = 30
9 u + 20 u = 29 u
29 u = 290
1 u = 290 ÷ 29 = 10
Number of pears in the stall
= 9 u
= 9 x 10
= 90
(b)
Number of oranges left
= 20 u
= 20 x 10
= 200
Number of bags
= 200 ÷ 4
= 50
Amount that he would receive
= 50 x 8.50
= $425
Answer(s): (a) 90; (b) $425