The ratio of the number of lemons to the number of limes that a fruit seller had was 3 : 8. After he sold one third of the limes, there were a total of 250 lemons and limes left at the supermarket.
- How many lemons were there at the supermarket?
- If he sold the remaining limes in bags of 4 at $5.60 per bag, how much would he receive for them?
(a)
|
Lemons |
Limes |
Total |
Before |
3x3 = 9 u
|
8x3 = 24 u |
|
Change |
|
- 8 u |
|
After |
9 u |
16 u |
250 |
The total number of limes at first is the repeated identity.
LCM of 8 and 3 = 24
9 u + 16 u = 25 u
25 u = 250
1 u = 250 ÷ 25 = 10
Number of lemons in the stall
= 9 u
= 9 x 10
= 90
(b)
Number of limes left
= 16 u
= 16 x 10
= 160
Number of bags
= 160 ÷ 4
= 40
Amount that he would receive
= 40 x 5.60
= $224
Answer(s): (a) 90; (b) $224