The ratio of the number of pomegranates to the number of limes that a fruit seller had was 3 : 8. After he sold one quarter of the limes, there were a total of 288 pomegranates and limes left at the mart.
- How many pomegranates were there at the mart?
- If he sold the remaining limes in bags of 4 at $3.50 per bag, how much would he receive for them?
(a)
|
Pomegranates |
Limes |
Total |
Before |
3x4 = 12 u
|
8x4 = 32 u |
|
Change |
|
- 8 u |
|
After |
12 u |
24 u |
288 |
The total number of limes at first is the repeated identity.
LCM of 8 and 4 = 32
12 u + 24 u = 36 u
36 u = 288
1 u = 288 ÷ 36 = 8
Number of pomegranates in the stall
= 12 u
= 12 x 8
= 96
(b)
Number of limes left
= 24 u
= 24 x 8
= 192
Number of bags
= 192 ÷ 4
= 48
Amount that he would receive
= 48 x 3.50
= $168
Answer(s): (a) 96; (b) $168