The ratio of the number of pears to the number of limes that a fruit seller had was 2 : 5. After he sold one fifth of the limes, there were a total of 210 pears and limes left at the market.
- How many pears were there at the market?
- If he sold the remaining limes in bags of 7 at $3.40 per bag, how much would he receive for them?
(a)
|
Pears |
Limes |
Total |
Before |
2x5 = 10 u
|
5x5 = 25 u |
|
Change |
|
- 5 u |
|
After |
10 u |
20 u |
210 |
The total number of limes at first is the repeated identity.
LCM of 5 and 5 = 25
10 u + 20 u = 30 u
30 u = 210
1 u = 210 ÷ 30 = 7
Number of pears in the stall
= 10 u
= 10 x 7
= 70
(b)
Number of limes left
= 20 u
= 20 x 7
= 140
Number of bags
= 140 ÷ 7
= 20
Amount that he would receive
= 20 x 3.40
= $68
Answer(s): (a) 70; (b) $68