The ratio of the number of limes to the number of mangosteens that a fruit seller had was 2 : 5. After he sold one fifth of the mangosteens, there were a total of 270 limes and mangosteens left at the stall.
- How many limes were there at the stall?
- If he sold the remaining mangosteens in bags of 6 at $8.30 per bag, how much would he receive for them?
(a)
|
Limes |
Mangosteens |
Total |
Before |
2x5 = 10 u
|
5x5 = 25 u |
|
Change |
|
- 5 u |
|
After |
10 u |
20 u |
270 |
The total number of mangosteens at first is the repeated identity.
LCM of 5 and 5 = 25
10 u + 20 u = 30 u
30 u = 270
1 u = 270 ÷ 30 = 9
Number of limes in the stall
= 10 u
= 10 x 9
= 90
(b)
Number of mangosteens left
= 20 u
= 20 x 9
= 180
Number of bags
= 180 ÷ 6
= 30
Amount that he would receive
= 30 x 8.30
= $249
Answer(s): (a) 90; (b) $249