There were 61 silver, green and grey pencils in a box. 11 grey pencils were removed from the box and the ratio of the number of silver pencils to the number of green pencils to the number of grey pencils became 2 : 5 : 3. Then some black pencils were added and the ratio of the number of grey pencils to the number of black pencils was 3 : 3.
- What was the ratio of the number of silver pencils to the number of green pencils to the number of grey pencils at first?
- How many pencils were in the box in the end?
|
Silver |
Green |
Grey |
Black |
Total |
Before |
2 u |
5 u |
3 u + 11 |
0 |
61 |
Change 1 |
No change |
No change |
- 11 |
|
- 11 |
After 1 |
2 u |
5 u |
3 u |
|
50 |
Change 2 |
No change |
No change |
No change |
+ 3 u |
|
After 2 |
2 u |
5 u |
3 u |
3 u |
|
(a)
Total number of pencils at first
= 2 u + 5 u + 3 u + 11
= 10 u + 11
10 u + 11 = 61
10 u = 61 - 11
10 u = 50
1 u = 50 ÷ 10 = 5
Number of silver pencils at first
= 2 u
= 2 x 5
= 10
Number of green pencils at first
= 5 u
= 5 x 5
= 25
Number of grey pencils at first
= 3 u + 11
= 3 x 5 + 11
= 26
At first
Silver pencils : Green pencils : Grey pencils
10 : 25 : 26
(b)
Total number of pencils in the box in the end
= 2 u + 5 u + 3 u + 3 u
= 13 u
= 65
Answer(s): (a) 10 : 25 : 26; (b) 65