There were some silver, blue and red markers in a box.
110 of the markers were blue. The ratio of the number of silver markers to the number of red markers was 4 : 5. There were 308 fewer blue markers than red markers.
- Find the ratio of the number of silver markers to the number of blue markers to the number of red markers in the box.
- How many red markers were there?
Blue |
Silver |
Red |
Total |
1 |
9 |
10 |
|
4 |
5 |
|
1 u |
4 u |
5 u |
10 u |
(a)
Silver : Blue : Red
4 : 1 : 5
(b)
Number of fewer blue markers than red markers
= 5 u - 1 u
= 4 u
4 u = 308
1 u = 308 ÷ 4 = 77
Number of red markers
= 5 u
= 5 x 77
= 385
Answer(s): (a) 4 : 1 : 5; (b) 385