There were some silver, blue and red markers in a box.
112 of the markers were blue. The ratio of the number of silver markers to the number of red markers was 4 : 7. There were 342 fewer blue markers than red markers.
- Find the ratio of the number of silver markers to the number of blue markers to the number of red markers in the box.
- How many red markers were there?
Blue |
Silver |
Red |
Total |
1 |
11 |
12 |
|
4 |
7 |
|
1 u |
4 u |
7 u |
12 u |
(a)
Silver : Blue : Red
4 : 1 : 7
(b)
Number of fewer blue markers than red markers
= 7 u - 1 u
= 6 u
6 u = 342
1 u = 342 ÷ 6 = 57
Number of red markers
= 7 u
= 7 x 57
= 399
Answer(s): (a) 4 : 1 : 7; (b) 399