A bag contained white, brown and gold notebooks.
25 of the notebooks were white and
49 of the remainder were brown notebooks.The rest were gold notebooks.
- Find the ratio of the number of gold notebooks to the number of white notebooks.
- There were 194 fewer brown notebooks than white notebooks. How many notebooks were there in the bag?
White notebooks |
Brown notebooks |
Gold notebooks |
2x3 |
3x3 |
|
4x1 |
5x1 |
6 u |
4 u |
5 u |
(a)
Fraction of white notebooks =
25 Fraction of notebooks that are not white = 1 -
25 =
35Remaining fraction of brown notebooks =
49Remaining fraction of gold notebooks = 1 -
49 =
59The total number of brown notebooks and gold notebooks is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 3 and 9 = 9
Gold notebooks : White notebooks
5 : 6
(b)
Difference in the number of white notebooks and brown notebooks
= 6 u - 4 u
= 2 u
2 u = 194
1 u = 194 ÷ 2 = 97
Total number of notebooks
= 6 u + 4 u + 5 u
= 15 u
= 15 x 97
= 1455
Answer(s): (a) 5 : 6; (b) 1455