A packet contained brown, white and gold pens.
35 of the pens were brown and
49 of the remainder were white pens.The rest were gold pens.
- Find the ratio of the number of gold pens to the number of brown pens.
- There were 171 fewer white pens than brown pens. How many pens were there in the packet?
| Brown pens |
White pens |
Gold pens |
| 3x9 |
2x9 |
| |
4x2 |
5x2 |
| 27 u |
8 u |
10 u |
(a)
Fraction of brown pens =
35 Fraction of pens that are not brown = 1 -
35 =
25Remaining fraction of white pens =
49Remaining fraction of gold pens = 1 -
49 =
59The total number of white pens and gold pens is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 2 and 9 = 18
Gold pens : Brown pens
10 : 27
(b)
Difference in the number of brown pens and white pens
= 27 u - 8 u
= 19 u
19 u = 171
1 u = 171 ÷ 19 = 9
Total number of pens
= 27 u + 8 u + 10 u
= 45 u
= 45 x 9
= 405
Answer(s): (a) 10 : 27; (b) 405
