A packet contained red, pink and brown files.
35 of the files were red and
35 of the remainder were pink files.The rest were brown files.
- Find the ratio of the number of brown files to the number of red files.
- There were 198 fewer pink files than red files. How many files were there in the packet?
| Red files |
Pink files |
Brown files |
| 3x5 |
2x5 |
| |
3x2 |
2x2 |
| 15 u |
6 u |
4 u |
(a)
Fraction of red files =
35 Fraction of files that are not red = 1 -
35 =
25Remaining fraction of pink files =
35Remaining fraction of brown files = 1 -
35 =
25The total number of pink files and brown files is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 2 and 5 = 10
Brown files : Red files
4 : 15
(b)
Difference in the number of red files and pink files
= 15 u - 6 u
= 9 u
9 u = 198
1 u = 198 ÷ 9 = 22
Total number of files
= 15 u + 6 u + 4 u
= 25 u
= 25 x 22
= 550
Answer(s): (a) 4 : 15; (b) 550
