A packet contained green, purple and yellow markers. ³₅ of the markers were green and ¹₉ of the remainder were purple markers.The rest were yellow markers.

1. Find the ratio of the number of yellow markers to the number of green markers.
2. There were 200 fewer purple markers than green markers. How many markers were there in the packet?

Green markers	Purple markers	Yellow markers
3x9	2x9
	1x2	8x2
27 u	2 u	16 u

(a)
Fraction of green markers = ³₅
Fraction of markers that are not green = 1 - ³₅ = ²₅

Remaining fraction of purple markers = ¹₉
Remaining fraction of yellow markers = 1 - ¹₉ = ⁸₉

The total number of purple markers and yellow markers is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 2 and 9 = 18

Yellow markers : Green markers
16 : 27

(b)
Difference in the number of green markers and purple markers
= 27 u - 2 u
= 25 u

25 u = 200
1 u = 200 ÷ 25 = 8

Total number of markers
= 27 u + 2 u + 16 u
= 45 u
= 45 x 8
= 360

Answer(s): (a) 16 : 27; (b) 360