A bag contained gold, yellow and blue pens.
35 of the pens were gold and
38 of the remainder were yellow pens.The rest were blue pens.
- Find the ratio of the number of blue pens to the number of gold pens.
- There were 153 fewer yellow pens than gold pens. How many pens were there in the bag?
| Gold pens |
Yellow pens |
Blue pens |
| 3x4 |
2x4 |
| |
3x1 |
5x1 |
| 12 u |
3 u |
5 u |
(a)
Fraction of gold pens =
35 Fraction of pens that are not gold = 1 -
35 =
25Remaining fraction of yellow pens =
38Remaining fraction of blue pens = 1 -
38 =
58The total number of yellow pens and blue pens is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 2 and 8 = 8
Blue pens : Gold pens
5 : 12
(b)
Difference in the number of gold pens and yellow pens
= 12 u - 3 u
= 9 u
9 u = 153
1 u = 153 ÷ 9 = 17
Total number of pens
= 12 u + 3 u + 5 u
= 20 u
= 20 x 17
= 340
Answer(s): (a) 5 : 12; (b) 340
