A bag contained blue, purple and silver staplers.
35 of the staplers were blue and
49 of the remainder were purple staplers.The rest were silver staplers.
- Find the ratio of the number of silver staplers to the number of blue staplers.
- There were 171 fewer purple staplers than blue staplers. How many staplers were there in the bag?
Blue staplers |
Purple staplers |
Silver staplers |
3x9 |
2x9 |
|
4x2 |
5x2 |
27 u |
8 u |
10 u |
(a)
Fraction of blue staplers =
35 Fraction of staplers that are not blue = 1 -
35 =
25Remaining fraction of purple staplers =
49Remaining fraction of silver staplers = 1 -
49 =
59The total number of purple staplers and silver staplers is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 2 and 9 = 18
Silver staplers : Blue staplers
10 : 27
(b)
Difference in the number of blue staplers and purple staplers
= 27 u - 8 u
= 19 u
19 u = 171
1 u = 171 ÷ 19 = 9
Total number of staplers
= 27 u + 8 u + 10 u
= 45 u
= 45 x 9
= 405
Answer(s): (a) 10 : 27; (b) 405