A packet contained gold, grey and yellow markers. ²₅ of the markers were gold and ⁴₉ of the remainder were grey markers.The rest were yellow markers.

1. Find the ratio of the number of yellow markers to the number of gold markers.
2. There were 148 fewer grey markers than gold markers. How many markers were there in the packet?

Gold markers	Grey markers	Yellow markers
2x3	3x3
	4x1	5x1
6 u	4 u	5 u

(a)
Fraction of gold markers = ²₅
Fraction of markers that are not gold = 1 - ²₅ = ³₅

Remaining fraction of grey markers = ⁴₉
Remaining fraction of yellow markers = 1 - ⁴₉ = ⁵₉

The total number of grey markers and yellow markers is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 3 and 9 = 9

Yellow markers : Gold markers
5 : 6

(b)
Difference in the number of gold markers and grey markers
= 6 u - 4 u
= 2 u

2 u = 148
1 u = 148 ÷ 2 = 74

Total number of markers
= 6 u + 4 u + 5 u
= 15 u
= 15 x 74
= 1110

Answer(s): (a) 5 : 6; (b) 1110