A packet contained pink, purple and grey pens.
25 of the pens were pink and
49 of the remainder were purple pens.The rest were grey pens.
- Find the ratio of the number of grey pens to the number of pink pens.
- There were 152 fewer purple pens than pink pens. How many pens were there in the packet?
| Pink pens |
Purple pens |
Grey pens |
| 2x3 |
3x3 |
| |
4x1 |
5x1 |
| 6 u |
4 u |
5 u |
(a)
Fraction of pink pens =
25 Fraction of pens that are not pink = 1 -
25 =
35Remaining fraction of purple pens =
49Remaining fraction of grey pens = 1 -
49 =
59The total number of purple pens and grey pens is the repeated identity.
Make the repeated identity the same by using LCM.
LCM of 3 and 9 = 9
Grey pens : Pink pens
5 : 6
(b)
Difference in the number of pink pens and purple pens
= 6 u - 4 u
= 2 u
2 u = 152
1 u = 152 ÷ 2 = 76
Total number of pens
= 6 u + 4 u + 5 u
= 15 u
= 15 x 76
= 1140
Answer(s): (a) 5 : 6; (b) 1140
