The ratio of the number of geese in Farm S to the number of geese in Farm T was 4 : 9. There were 50 fewer geese in Farm S than in Farm T. When 12 geese escaped from Farm T, the farmer in Farm T bought another 17 geese. What was the new ratio of the number of geese in Farm S to the number of geese in Farm T in the end? Give your answer in the simplest form.
|
Farm S |
Farm T |
Before |
4 u |
9 u |
Change 1 |
|
- 12 |
Change 2 |
|
+ 17 |
After |
4 u |
9 u + 5 |
Number of fewer geese in Farm S than Farm T
= 9 u - 4 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of geese in Farm S
= 4 u
= 10 x 4
= 40
Number of geese in Farm T
= 9 u
= 10 x 9
= 90
New number of geese in Farm T
= 9 u + 5
= 90 + 5
= 95
Farm S : Farm T
40 : 95
(÷ 5)8 : 19
Answer(s): 8 : 19