The ratio of the number of hens in Farm S to the number of hens in Farm T was 4 : 7. There were 69 more hens in Farm T than in Farm S. When 7 hens escaped from Farm T, the farmer in Farm T bought another 14 hens. What was the new ratio of the number of hens in Farm S to the number of hens in Farm T in the end? Give your answer in the simplest form.
| |
Farm S |
Farm T |
| Before |
4 u |
7 u |
| Change 1 |
|
- 7 |
| Change 2 |
|
+ 14 |
| After |
4 u |
7 u + 7 |
Number of more hens in Farm T than Farm S
= 7 u - 4 u
= 3 u
3 u = 69
1 u = 69 ÷ 3 = 23
Number of hens in Farm S
= 4 u
= 23 x 4
= 92
Number of hens in Farm T
= 7 u
= 23 x 7
= 161
New number of hens in Farm T
= 7 u + 7
= 161 + 7
= 168
Farm S : Farm T
92 : 168
(÷ 4)23 : 42
Answer(s): 23 : 42
