The ratio of the number of chickens in Farm Y to the number of chickens in Farm Z was 3 : 5. There were 42 more chickens in Farm Z than in Farm Y. When 5 chickens escaped from Farm Z, the farmer in Farm Z bought another 20 chickens. What was the new ratio of the number of chickens in Farm Y to the number of chickens in Farm Z in the end? Give your answer in the simplest form.
|
Farm Y |
Farm Z |
Before |
3 u |
5 u |
Change 1 |
|
- 5 |
Change 2 |
|
+ 20 |
After |
3 u |
5 u + 15 |
Number of more chickens in Farm Z than Farm Y
= 5 u - 3 u
= 2 u
2 u = 42
1 u = 42 ÷ 2 = 21
Number of chickens in Farm Y
= 3 u
= 21 x 3
= 63
Number of chickens in Farm Z
= 5 u
= 21 x 5
= 105
New number of chickens in Farm Z
= 5 u + 15
= 105 + 15
= 120
Farm Y : Farm Z
63 : 120
(÷ 3)21 : 40
Answer(s): 21 : 40