In the figure, ∠NQP = 90°. ∠NQR is 34° more than ∠PQR.
- What line is perpendicular to NQ?
- Find ∠NQR.
(a)
Line PQ or QP is perpendicular to NQ.
(b)
∠PQR = 1 u
∠NQR = 1 u + 34
1 u + 1 u + 34° = 90° (Right angle)
2 u = 90° - 34° = 56°
1 u = 56° ÷ 2 = 28°
∠NQR
= 28° + 34°
= 62°
Answer(s): (a) PQ or QP; (b) 62°