In the figure, ∠BDC = 90°. ∠BDE is 33° more than ∠CDE.
- What line is perpendicular to BD?
- Find ∠BDE.
(a)
Line CD or DC is perpendicular to BD.
(b)
∠CDE = 1 u
∠BDE = 1 u + 33
1 u + 1 u + 33° = 90° (Right angle)
2 u = 90° - 33° = 57°
1 u = 57° ÷ 2 = 28.5°
∠BDE
= 28.5° + 33°
= 61.5°
Answer(s): (a) CD or DC; (b) 61.5°