In the figure, ∠BDC = 90°. ∠BDE is 30° more than ∠CDE.
- What line is perpendicular to BD?
- Find ∠BDE.
(a)
Line CD or DC is perpendicular to BD.
(b)
∠CDE = 1 u
∠BDE = 1 u + 30
1 u + 1 u + 30° = 90° (Right angle)
2 u = 90° - 30° = 60°
1 u = 60° ÷ 2 = 30°
∠BDE
= 30° + 30°
= 60°
Answer(s): (a) CD or DC; (b) 60°