In the figure, ∠JLK = 90°. ∠JLM is 33° more than ∠KLM.
- What line is perpendicular to JL?
- Find ∠JLM.
(a)
Line KL or LK is perpendicular to JL.
(b)
∠KLM = 1 u
∠JLM = 1 u + 33
1 u + 1 u + 33° = 90° (Right angle)
2 u = 90° - 33° = 57°
1 u = 57° ÷ 2 = 28.5°
∠JLM
= 28.5° + 33°
= 61.5°
Answer(s): (a) KL or LK; (b) 61.5°