In the figure, ∠JLK = 90°. ∠JLM is 32° more than ∠KLM.
- What line is perpendicular to JL?
- Find ∠JLM.
(a)
Line KL or LK is perpendicular to JL.
(b)
∠KLM = 1 u
∠JLM = 1 u + 32
1 u + 1 u + 32° = 90° (Right angle)
2 u = 90° - 32° = 58°
1 u = 58° ÷ 2 = 29°
∠JLM
= 29° + 32°
= 61°
Answer(s): (a) KL or LK; (b) 61°