In the figure, ∠BDC = 90°. ∠BDE is 35° more than ∠CDE.
- What line is perpendicular to BD?
- Find ∠BDE.
(a)
Line CD or DC is perpendicular to BD.
(b)
∠CDE = 1 u
∠BDE = 1 u + 35
1 u + 1 u + 35° = 90° (Right angle)
2 u = 90° - 35° = 55°
1 u = 55° ÷ 2 = 27.5°
∠BDE
= 27.5° + 35°
= 62.5°
Answer(s): (a) CD or DC; (b) 62.5°