In the figure, KL is a straight line. ∠JMK = 90°, ∠NMP is equal to ∠PML but 27° more than ∠JMN.
- What line is perpendicular to KL?
- Find ∠NMP.
(a)
Line JM or MJ is perpendicular to KL
(b)
∠NMP = ∠PML = 1 u
∠JMN = 1 u - 27°
1 u + 1 u + 1 u - 27° = 90° (Right angle)
3 u = 90° + 27° = 117°
1 u = 117° ÷ 3 = 39°
Answer(s): (a) JM or MJ; (b) 39°