In the figure, FG is a straight line. ∠EHF = 90°, ∠JHK is equal to ∠KHG but 30° more than ∠EHJ.
- What line is perpendicular to FG?
- Find ∠JHK.
(a)
Line EH or HE is perpendicular to FG
(b)
∠JHK = ∠KHG = 1 u
∠EHJ = 1 u - 30°
1 u + 1 u + 1 u - 30° = 90° (Right angle)
3 u = 90° + 30° = 120°
1 u = 120° ÷ 3 = 40°
Answer(s): (a) EH or HE; (b) 40°