The figure shows a square BCFG and a rectangle CDEF. ∠DGF = 44°.
- Find ∠CJG.
- Find ∠BHD.
(a)
∠CJG
= 44° + 90°
= 134° (Exterior angle of a triangle)
(b)
∠BFG = 45°
∠FHG
= 180° - 44° - 45°
= 91° (Angles sum of triangle)
∠BHD
= ∠FHG
= 91° (Vertically opposite angles)
Answer(s): (a) 134°; (b) 91°