The figure shows a square HJMN and a rectangle JKLM. ∠KNM = 37°.
- Find ∠JQN.
- Find ∠HPK.
(a)
∠JQN
= 37° + 90°
= 127° (Exterior angle of a triangle)
(b)
∠HMN = 45°
∠MPN
= 180° - 37° - 45°
= 98° (Angles sum of triangle)
∠HPK
= ∠MPN
= 98° (Vertically opposite angles)
Answer(s): (a) 127°; (b) 98°