The figure shows a square DEHJ and a rectangle EFGH. ∠FJH = 38°.
- Find ∠ELJ.
- Find ∠DKF.
(a)
∠ELJ
= 38° + 90°
= 128° (Exterior angle of a triangle)
(b)
∠DHJ = 45°
∠HKJ
= 180° - 38° - 45°
= 97° (Angles sum of triangle)
∠DKF
= ∠HKJ
= 97° (Vertically opposite angles)
Answer(s): (a) 128°; (b) 97°