The figure shows a square DEHJ and a rectangle EFGH. ∠FJH = 42°.
- Find ∠ELJ.
- Find ∠DKF.
(a)
∠ELJ
= 42° + 90°
= 132° (Exterior angle of a triangle)
(b)
∠DHJ = 45°
∠HKJ
= 180° - 42° - 45°
= 93° (Angles sum of triangle)
∠DKF
= ∠HKJ
= 93° (Vertically opposite angles)
Answer(s): (a) 132°; (b) 93°