The figure shows a square HJMN and a rectangle JKLM. ∠KNM = 40°.
- Find ∠JQN.
- Find ∠HPK.
(a)
∠JQN
= 40° + 90°
= 130° (Exterior angle of a triangle)
(b)
∠HMN = 45°
∠MPN
= 180° - 40° - 45°
= 95° (Angles sum of triangle)
∠HPK
= ∠MPN
= 95° (Vertically opposite angles)
Answer(s): (a) 130°; (b) 95°